Optimal. Leaf size=543 \[ -\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}-\frac{9 a e^{11/2} \left (b^2-a^2\right )^{5/4} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 b^{11/2} d}-\frac{9 a e^{11/2} \left (b^2-a^2\right )^{5/4} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 b^{11/2} d}-\frac{3 e^6 \left (-28 a^2 b^2+21 a^4+5 b^4\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 b^6 d \sqrt{e \cos (c+d x)}}+\frac{9 a^2 e^6 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 d \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{9 a^2 e^6 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 d \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))} \]
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Rubi [A] time = 1.5189, antiderivative size = 543, normalized size of antiderivative = 1., number of steps used = 15, number of rules used = 12, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.48, Rules used = {2693, 2865, 2867, 2642, 2641, 2702, 2807, 2805, 329, 212, 208, 205} \[ -\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}-\frac{9 a e^{11/2} \left (b^2-a^2\right )^{5/4} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 b^{11/2} d}-\frac{9 a e^{11/2} \left (b^2-a^2\right )^{5/4} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{2 b^{11/2} d}-\frac{3 e^6 \left (-28 a^2 b^2+21 a^4+5 b^4\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 b^6 d \sqrt{e \cos (c+d x)}}+\frac{9 a^2 e^6 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 d \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{9 a^2 e^6 \left (a^2-b^2\right )^2 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 d \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{e \cos (c+d x)}}+\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))} \]
Antiderivative was successfully verified.
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Rule 2693
Rule 2865
Rule 2867
Rule 2642
Rule 2641
Rule 2702
Rule 2807
Rule 2805
Rule 329
Rule 212
Rule 208
Rule 205
Rubi steps
\begin{align*} \int \frac{(e \cos (c+d x))^{11/2}}{(a+b \sin (c+d x))^2} \, dx &=-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{\left (9 e^2\right ) \int \frac{(e \cos (c+d x))^{7/2} \sin (c+d x)}{a+b \sin (c+d x)} \, dx}{2 b}\\ &=\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{\left (9 e^4\right ) \int \frac{(e \cos (c+d x))^{3/2} \left (-a b-\frac{1}{2} \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{a+b \sin (c+d x)} \, dx}{7 b^3}\\ &=\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}-\frac{\left (6 e^6\right ) \int \frac{\frac{1}{2} a b \left (7 a^2-8 b^2\right )+\frac{1}{4} \left (21 a^4-28 a^2 b^2+5 b^4\right ) \sin (c+d x)}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))} \, dx}{7 b^5}\\ &=\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}+\frac{\left (9 a \left (a^2-b^2\right )^2 e^6\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} (a+b \sin (c+d x))} \, dx}{2 b^6}-\frac{\left (3 \left (21 a^4-28 a^2 b^2+5 b^4\right ) e^6\right ) \int \frac{1}{\sqrt{e \cos (c+d x)}} \, dx}{14 b^6}\\ &=\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}-\frac{\left (9 a^2 \left (-a^2+b^2\right )^{3/2} e^6\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{4 b^6}-\frac{\left (9 a^2 \left (-a^2+b^2\right )^{3/2} e^6\right ) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{4 b^6}+\frac{\left (9 a \left (a^2-b^2\right )^2 e^7\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (\left (a^2-b^2\right ) e^2+b^2 x^2\right )} \, dx,x,e \cos (c+d x)\right )}{2 b^5 d}-\frac{\left (3 \left (21 a^4-28 a^2 b^2+5 b^4\right ) e^6 \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx}{14 b^6 \sqrt{e \cos (c+d x)}}\\ &=-\frac{3 \left (21 a^4-28 a^2 b^2+5 b^4\right ) e^6 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 b^6 d \sqrt{e \cos (c+d x)}}+\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}+\frac{\left (9 a \left (a^2-b^2\right )^2 e^7\right ) \operatorname{Subst}\left (\int \frac{1}{\left (a^2-b^2\right ) e^2+b^2 x^4} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{b^5 d}-\frac{\left (9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{4 b^6 \sqrt{e \cos (c+d x)}}-\frac{\left (9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{4 b^6 \sqrt{e \cos (c+d x)}}\\ &=-\frac{3 \left (21 a^4-28 a^2 b^2+5 b^4\right ) e^6 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 b^6 d \sqrt{e \cos (c+d x)}}+\frac{9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 \left (b-\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}-\frac{9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 \left (b+\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}+\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}-\frac{\left (9 a \left (-a^2+b^2\right )^{3/2} e^6\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e-b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{2 b^5 d}-\frac{\left (9 a \left (-a^2+b^2\right )^{3/2} e^6\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e+b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{2 b^5 d}\\ &=-\frac{9 a \left (-a^2+b^2\right )^{5/4} e^{11/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{2 b^{11/2} d}-\frac{9 a \left (-a^2+b^2\right )^{5/4} e^{11/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{2 b^{11/2} d}-\frac{3 \left (21 a^4-28 a^2 b^2+5 b^4\right ) e^6 \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{7 b^6 d \sqrt{e \cos (c+d x)}}+\frac{9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 \left (b-\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}-\frac{9 a^2 \left (-a^2+b^2\right )^{3/2} e^6 \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{2 b^6 \left (b+\sqrt{-a^2+b^2}\right ) d \sqrt{e \cos (c+d x)}}+\frac{9 e^3 (e \cos (c+d x))^{5/2} (7 a-5 b \sin (c+d x))}{35 b^3 d}-\frac{e (e \cos (c+d x))^{9/2}}{b d (a+b \sin (c+d x))}-\frac{3 e^5 \sqrt{e \cos (c+d x)} \left (21 a \left (a^2-b^2\right )-b \left (7 a^2-5 b^2\right ) \sin (c+d x)\right )}{7 b^5 d}\\ \end{align*}
Mathematica [C] time = 27.7261, size = 2030, normalized size = 3.74 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 10.645, size = 19829, normalized size = 36.5 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \cos \left (d x + c\right )\right )^{\frac{11}{2}}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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